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Jan (talk | contribs)
x'(n)=sum(i=1:p:a(i)x(n-i))
 
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Latest revision as of 19:57, 25 March 2005

x'(n)=sum(i=1:p:a(i)x(n-i))

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current19:57, 25 March 2005Thumbnail for version as of 19:57, 25 March 2005136 × 46 (1 KB)Jan (talk | contribs)x'(n)=sum(i=1:p:a(i)x(n-i))

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