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x'(n)=sum(i=1:p:a(i)x(n-i)) |
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Latest revision as of 19:57, 25 March 2005
x'(n)=sum(i=1:p:a(i)x(n-i))
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 19:57, 25 March 2005 | 136 × 46 (1 KB) | Jan (talk | contribs) | x'(n)=sum(i=1:p:a(i)x(n-i)) |
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